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湖北省省實(shí)驗(yàn)中學(xué)2009屆高三年級(jí)理科綜合能力測(cè)試(十)        命題人:黃瓊 高曉軍 龍信和        時(shí)間:150分鐘  總分300

I卷(共126分)

以下數(shù)據(jù)可供解題時(shí)參考:相對(duì)原子質(zhì)量(原子量): Mg   24; Al  27

試題詳情

本資料來(lái)源于《七彩教育網(wǎng)》http://www.7caiedu.cn

《解三角形》

 

試題詳情

海南省國(guó)興中學(xué) 海師附中 嘉積中學(xué) 三亞一中2009年高三聯(lián)考物理科試卷

注意事項(xiàng):

1.本試卷分第I卷(選擇題)和第II卷(非選擇題)兩部分。答卷前,請(qǐng)考生務(wù)必將自己的姓名、準(zhǔn)考證號(hào)填寫在答題卡上。

2.回答第I卷時(shí),選出小題答案后,用鉛筆把答題卡上對(duì)應(yīng)題目的答案標(biāo)號(hào)涂黑。如需改動(dòng),用橡皮擦干凈后,用再選涂其它答案標(biāo)號(hào)。寫在本試卷上無(wú)效。

3.回答第II卷時(shí),將答案寫在答題卡上。寫在本試卷上無(wú)效。

4.考試結(jié)束后,將本試卷和答題卡一并交回。

 

第Ⅰ卷(選擇題,共34分)

試題詳情

揭陽(yáng)華僑中學(xué)高三物理練習(xí)題 2009-05-07

1.下面列舉的事例中正確的是(     ).

A.居里夫婦用α粒子轟擊鋁箔時(shí)發(fā)現(xiàn)了正電子

B.盧瑟福的原子結(jié)構(gòu)學(xué)說(shuō)成功地解釋了氫原子的發(fā)光現(xiàn)象

C.麥克斯韋從理論上預(yù)言了電磁波的存在,赫茲用實(shí)驗(yàn)方法給予證實(shí)

D.玻爾建立了量子理論,解釋了各種原子發(fā)光現(xiàn)象

 

2.氫原子的核外電子從一個(gè)軌道躍遷到另一軌道時(shí),可能發(fā)生的情況有

A.放出光子,電子動(dòng)能減少,原子勢(shì)能增加

B.放出光子,電子動(dòng)能增加,原子勢(shì)能減少

C.吸收光子,電子動(dòng)能減少,原子勢(shì)能增加

D.吸收光子,電子動(dòng)能增加,原子勢(shì)能減少

 

3.如圖所示,一驗(yàn)電器與鋅板相連,現(xiàn)用一弧光燈照射鋅板,關(guān)燈后,指針保持一定偏角,下列判斷中正確的是

A.用一帶負(fù)電(帶電量較少)的金屬小球與鋅板接觸,則驗(yàn)電器指針偏角將增大

B.用一帶負(fù)電(帶電量較少)的金屬小球與鋅板接觸,則驗(yàn)電器指針偏角將減小

C.使驗(yàn)電器指針回到零后,改用強(qiáng)度更大的弧光燈照射鋅板,驗(yàn)電器指針偏角將比原來(lái)大

D.使驗(yàn)電器指針回到零后,改用強(qiáng)度更大的紅外線燈照射鋅板,驗(yàn)電器指針一定偏轉(zhuǎn)

 

4.放在光滑水平面上的物塊1、2用輕質(zhì)彈簧秤相連,如圖所示.今對(duì)物塊1、2分別施以相反的水平力F1 、F2.且F1大于F2,則彈簧秤的示數(shù)

A.一定等于F1+F2

B.一定等于F1-F2               

C.一定大于F2小于F1

D.條件不足,無(wú)法確定

 

5.如圖所示,斜面體P放在水平面上,物體Q放在斜面上.Q受一水平作用力F,Q和P都靜止.這時(shí)P對(duì)Q的靜摩擦力和水平面對(duì)P的靜摩擦力分別為f1、f2.現(xiàn)使力F變大,系統(tǒng)仍靜止,則

A. f1、f2都變大           B.f1、f2都不一定變大

C. f1變大,f2不一定變大   D. f2變大,f1不一定變大 

 

6.如圖所示,質(zhì)量為m的木塊在質(zhì)量為M的長(zhǎng)木板上向右滑行,木塊同時(shí)受到向右的拉力F的作用,長(zhǎng)木板處于靜止?fàn)顟B(tài);已知木塊與木板間的動(dòng)摩擦因數(shù)為μ1,木板與地面間的動(dòng)摩擦因數(shù)為μ2,則

A.木板受到地面的摩擦力的大小一定是μ1mg

B.木板受到地面的摩擦力的大小一定是μ2(m十M)g

C.當(dāng)F>μ2(m+M)g時(shí),木板便會(huì)開(kāi)始運(yùn)動(dòng)

D.無(wú)論怎樣改變F的大小,木板都不可能運(yùn)動(dòng)

7.如圖所示,在臺(tái)秤的托盤上放著一個(gè)支架,支架上掛著一個(gè)電磁鐵A,電磁鐵的正下方有一鐵塊B,電磁鐵不通電時(shí),臺(tái)秤示數(shù)為G,當(dāng)接通電路,在鐵塊被吸起上升的過(guò)程中,臺(tái)秤的示數(shù)將                                           

A.不變                                       B.變大

C.變小                                           D.忽大忽小

 

8.如圖所示,甲、乙兩電路中電源完全相同,電阻R1>R2,在兩電路中分別通過(guò)相同的電量Q的過(guò)程中,下列關(guān)于兩電路的比較,正確的是

  A.電源內(nèi)部產(chǎn)生電熱較多的是甲電路中的電源

  B.R1上產(chǎn)生的電熱比R2上產(chǎn)生的電熱多

  C.電源做功較多的是乙電路中的電源

  D.電源輸出功率較大的是乙電路中的電源

 

9.如圖所示,一個(gè)帶負(fù)電的油滴以初速v0從P點(diǎn)傾斜向上進(jìn)入水平方向的勻強(qiáng)電場(chǎng)中,若油滴到達(dá)最高點(diǎn)時(shí)速度大小仍為v0,則油滴最高點(diǎn)的位置在

A.P點(diǎn)的左上方     B.P點(diǎn)的右上方

C.P點(diǎn)的正上方     D.上述情況都可能

 

10.如圖所示,在圓形區(qū)域內(nèi)存在一垂直于紙面向里的勻強(qiáng)磁場(chǎng),一束速率各不相同的質(zhì)子從A點(diǎn)沿磁場(chǎng)圓形邊界的半徑方向射入磁場(chǎng)。關(guān)于質(zhì)子在該磁場(chǎng)內(nèi)運(yùn)動(dòng)過(guò)程的說(shuō)法正確的是

A.運(yùn)動(dòng)時(shí)間越長(zhǎng)的,其軌跡越長(zhǎng)

B.運(yùn)動(dòng)時(shí)間越長(zhǎng)的,其射出磁場(chǎng)時(shí)的速率越大

C.運(yùn)動(dòng)時(shí)間越長(zhǎng)的,其軌跡對(duì)應(yīng)的圓心角越大

D.運(yùn)動(dòng)時(shí)間越長(zhǎng)的,其速度方向的偏轉(zhuǎn)角越大

 

11.如圖所示,寬h=2cm的有界勻強(qiáng)磁場(chǎng),縱向范圍足夠大,磁感應(yīng)強(qiáng)度的方向垂直紙面向內(nèi),現(xiàn)有一群正粒子從O點(diǎn)以相同的速率沿紙面不同方向進(jìn)入磁場(chǎng),若粒子在磁場(chǎng)中做勻速圓周運(yùn)動(dòng)的軌道半徑均為r=5cm,則

A.右邊界:-4cm<y<4cm有粒子射出

B.右邊界:y>4cmy<-4cm有粒子射出

C.左邊界:y>8cm有粒子射出

D.左邊界:0<y<8cm有粒子射出

 

12.如圖所示,平行于紙面水平向右的勻強(qiáng)磁場(chǎng),磁感應(yīng)強(qiáng)度B1=1T。位于紙面內(nèi)的細(xì)直導(dǎo)線,長(zhǎng)L=1m,通有I=1A的恒定電流。當(dāng)導(dǎo)線與B1成600夾角時(shí),發(fā)現(xiàn)其受到的安培力為零。則該區(qū)域同時(shí)存在的另一勻強(qiáng)磁場(chǎng)的磁感應(yīng)強(qiáng)度B2大小可能值

A.T      B.T   

C.1 T       D.T

                  

13.(Ⅰ) (10分)某同學(xué)設(shè)計(jì)了一個(gè)探究加速度與物體所受合力F及質(zhì)量m間關(guān)系的實(shí)驗(yàn).圖(a)為實(shí)驗(yàn)裝置簡(jiǎn)圖,A為小車,B為打點(diǎn)計(jì)時(shí)器,C為裝有砂的砂桶,D為一端帶有定滑輪的長(zhǎng)方形木板,實(shí)驗(yàn)中認(rèn)為細(xì)繩對(duì)小車?yán)等于砂和砂桶總重力,小車運(yùn)動(dòng)加速度a可由紙帶上點(diǎn)求得.

 

 

 

 

 

 

 

 

 

次   數(shù)

1

2

3

4

5

6

7

8

小車加速度a/ms-2

1.90

1.72

1.49

1.25

1.00

0.75

0.50

0.30

小車質(zhì)量m/kg

0.25

0.29

0.33

0.40

0.50

0.71

1.00

1.67

4.00

3.50

3.00

2.5

2.00

1.40

1.00

0.60

(1)圖(b)為某次實(shí)驗(yàn)得到的紙帶(交流電的頻率為50Hz),由圖中數(shù)據(jù)求出小車加速度值為          _________m/s2;

 

 

 

 

 

 

 

 

 

 

(2)保持砂和砂桶質(zhì)量不變,改變小車質(zhì)量m,分別得到小車加速度a與質(zhì)量m及對(duì)應(yīng)的數(shù)據(jù)如表中所示,根據(jù)表中數(shù)據(jù),為直觀反映F不變時(shí)a與m的關(guān)系,請(qǐng)?jiān)诜礁褡鴺?biāo)紙中選擇恰當(dāng)物理量建立坐標(biāo)系,并作出圖線;

從圖線中得到F不變時(shí)小車加速度a與 質(zhì)量m間定量關(guān)系是_____________;

 

(3)保持小車質(zhì)量不變,改變砂和砂桶質(zhì)量,該同學(xué)根據(jù)實(shí)驗(yàn)數(shù)據(jù)作出了加速度a與合力F圖線如圖(C),該圖線不通過(guò)原點(diǎn),明顯超出偶然誤差范圍,其主要原因是:

                                                                        .

 

 

 

 

 

 

 

 

 

 (Ⅱ)某同學(xué)用如圖所示的實(shí)驗(yàn)裝置探究小車動(dòng)能變化與合外力對(duì)它所做功的關(guān)系。圖中A為小車,連接在小車后面的紙帶穿過(guò)打點(diǎn)計(jì)時(shí)器B的限位孔,它們均置于水平放置的一端帶有定滑輪的足夠長(zhǎng)的木板上,C為彈簧測(cè)力計(jì),不計(jì)繩與滑輪的摩擦。實(shí)驗(yàn)時(shí),先接通電源再松開(kāi)小車,打點(diǎn)計(jì)時(shí)器在紙帶上打下一系列點(diǎn)。

(1)該同學(xué)在一條比較理想的紙帶上,從點(diǎn)跡清楚的某點(diǎn)開(kāi)始記為O點(diǎn),順次選取5個(gè)點(diǎn),分別測(cè)量這5個(gè)點(diǎn)到O之間的距離,并計(jì)算出它們與O點(diǎn)之間的速度平方差:

 ,填入下表:

未標(biāo)題-5

為縱坐標(biāo),以s為橫坐標(biāo)在方格紙中作 

圖象.若測(cè)出小車質(zhì)量為0.2kg,結(jié)合圖 

象可求得小車所受合外力的大小為      N

(2)若該同學(xué)通過(guò)計(jì)算發(fā)現(xiàn)小車所受合外力小于測(cè)

學(xué)科網(wǎng)(Zxxk.Com)力計(jì)讀數(shù),明顯超出實(shí)驗(yàn)誤差的正常范圍.你認(rèn)

為主要原因是                            ,

實(shí)驗(yàn)操作中改進(jìn)的措施是                 

                                            。

 

 

 

 

14.在實(shí)驗(yàn)室中測(cè)量電源的電動(dòng)勢(shì)和內(nèi)電阻,可以提供的器材有:

a)待測(cè)電池:電動(dòng)勢(shì)E(約3V)、內(nèi)電阻r(約1Ω)

b)電壓表V:量程15V,內(nèi)電阻

c)電流表A1:量程0.6A,內(nèi)阻

d)電流表A2:量程1mA,內(nèi)阻r2=200Ω

e)滑動(dòng)變阻器R1:阻值0―200Ω,額定電流1.5A

f)滑動(dòng)變阻器R2:阻值0―20Ω,額定電流1.5A

g)電阻箱R3:9999Ω

以及開(kāi)關(guān),導(dǎo)線,坐標(biāo)紙等。

為了盡可能準(zhǔn)確地測(cè)量待測(cè)電池的電動(dòng)勢(shì)和內(nèi)電阻:

①實(shí)驗(yàn)所用器材除了待測(cè)電池和導(dǎo)線、開(kāi)關(guān)、坐標(biāo)紙等,還需選擇必要的器材有(填器材前的序號(hào))               。

②畫出測(cè)量電池電動(dòng)勢(shì)和內(nèi)電阻的電路圖。

③說(shuō)明測(cè)量的主要實(shí)驗(yàn)步驟。(要求用圖象法處理實(shí)驗(yàn)數(shù)據(jù)。)

 

15.如圖,圓環(huán)質(zhì)量為M,經(jīng)過(guò)環(huán)心的豎直鋼絲AB上套一質(zhì)量為m的小球,今將小球沿鋼絲AB以初速度v0從A點(diǎn)豎直向上拋出,致使環(huán)對(duì)地面剛好無(wú)壓力,求:

⑴ 小球上升的加速度。

⑵ 小球能達(dá)到的最大高度。(球不會(huì)碰到B點(diǎn))

 

 

16.(16分)如圖所示,MN為紙面內(nèi)一豎直分界線,P、D是紙面內(nèi)水平方向上的兩點(diǎn)。兩點(diǎn)之間的距離為L(zhǎng),D點(diǎn)距分界線的距離為,一質(zhì)量為m、電量為q的帶正電粒子在紙面內(nèi)從P點(diǎn)開(kāi)始以v0的水平初速度向右運(yùn)動(dòng),經(jīng)過(guò)一段時(shí)間后在MN左側(cè)空間加上垂直紙面向里的磁感應(yīng)強(qiáng)度為B的勻強(qiáng)磁場(chǎng),磁場(chǎng)維持t0時(shí)間后撤除,隨后粒子再次通過(guò)D點(diǎn)且速度方向豎直向下。粒子的重力不計(jì),求:

  (1) 粒子在加上磁場(chǎng)前運(yùn)動(dòng)的時(shí)間t.    、

  (2) 滿足題設(shè)條件的磁感應(yīng)強(qiáng)度B的最小值及B最小時(shí)t0的值.

 

 

試題詳情

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  《算法初步》

 

試題詳情

2009屆巢湖市第六中學(xué)高三

第六次月考

第一部分  聽(tīng)力(共兩節(jié),滿分30分)

第一節(jié)(共5小題;每小題1.5分,滿分7.5分)

       聽(tīng)下面5段對(duì)話。每段對(duì)話后有一個(gè)小題,從題中所給的A、B、C三個(gè)選項(xiàng)中選出最佳選項(xiàng),并標(biāo)在試卷的相應(yīng)位置。聽(tīng)完每段對(duì)話后,你都有10秒鐘的時(shí)間來(lái)回答有關(guān)小題和閱讀下一小題。每段對(duì)話僅讀一遍。

1. Which is the first program the woman is planning to watch?

A. A movie.        B. A cartoon.     C. A football game.

2. What can we learn from this conversation?

A. The wind has stopped but it's still raining.    B. The rain stopped.

C. It's still raining and the wind is blowing.

3. What country does Suzanne presently call her home?

A. America.        B. England.       C. Spain.

4. Where does the conversation take place?

A. In the man's house.    B. In a dinning-room.    C. In a restaurant.

5. What job is the man poking for?

A. He wants to be with the computer center.

B. He wants to work at a computer servicing company.

C. He wants to work in the computer market department.

第二節(jié) (共15小題;每題1.5分,滿分22.5分)

聽(tīng)下面5段對(duì)話或獨(dú)白。每段對(duì)話或獨(dú)白后有幾個(gè)小題,從題中所給的A,B,C三個(gè)選項(xiàng)中選出最佳選項(xiàng),并標(biāo)在試卷的相應(yīng)位置。聽(tīng)每段對(duì)話或獨(dú)白前,你將有時(shí)間閱讀各個(gè)小題,每小題5秒鐘;聽(tīng)完后,每小題將給出5秒鐘的作答時(shí)間。每段對(duì)話或獨(dú)白讀兩遍。

聽(tīng)第6段材料,回答第6―7題。

6. What kind of car does the woman want?

A. A new car.      B. A second-hand car.     C. A cheap car.

7. What happened to the woman's car?

A. It broke down.   B. It was stolen.     C. It was given to her son.

聽(tīng)第7段材料,回答第8―9題。

8. What does David want Julie to do?

A. To tell him her telephone number.   B. To go out with him.   C. To visit him.

9. When will they meet?

A. On Sunday.     B. On Saturday.           C. On Thursday.

聽(tīng)第8段材料,回答第10―12題。

10. Which statement is right?

A. The exam yesterday was harder than the last one.

B. The exam yesterday was shorter than the last one.

C. The exam yesterday was as easy as the last one.

11. Why did Mary make some stupid mistakes?

A. Because he didn’t work hard.    B. Because she didn’t take many courses.

C. Because she was too careless.

12. Who is a better student?

A. Mary.      B. Jimmy.  C. The man.

聽(tīng)第9段材料,回答第13―16題。

13. Who is answering the call?

A. Mary.      B. Jean.     C. Anna

14. Why is Pat making the telephone call?

A. To tell his friend to attend a meeting.

B. To tell his friend to hand in the experiment report.

C. To tell his friend to come to work for the Chemistry Department.

15. Who is Jean?

A. Annals sister-in-law.   B. Mary's sister-in-law.   C. Pat's friend.

16. Which of the following do you think is true?

A. Pat knows Mary.    B. Jean knows Pat.    C. Anna doesn't know Pat.

聽(tīng)第10段材料,回答第17―20題。

17. What is the purpose of the talk?

A. To describe a college training course.   B. To employ people for a job.

C. To talk about problems the airline company faces.

18. According to the speaker, how many people are accepted for the training program every year?     A. About one thousand.   

B. Several thousand.   C. Fewer than one thousand.

19. What subject matter does the speaker mention is included in the training?

A. Psychology.         B. Physical language.  C. Geography.

20. Why does the speaker mention headwaiters?

A. To explain her previous job.

B. To describe the background needed by people asking for the job.

C. To describe some of the skills people working in the plane need.

­

第二部分:知識(shí)運(yùn)用(共兩節(jié),滿分45分)

第一節(jié):?jiǎn)雾?xiàng)填空(每小題1分,滿分15分)

從A、B、C、D四個(gè)選項(xiàng)中,選出可以填入空白處的最佳選項(xiàng)。

21. ―_______ noise outside!   

―_______. I’ll close the doors and the windows. Now let’s go on.

A. What a; Not at all        B. How; That’s right

C. How; All right           D. What; Never mind

22. The hard-working farmers and their happy life we saw in the countryside________ us very much.

A. frightened          B. impressed            C. disappointed          D. expressed

23. Was it 8 o’clock _______ you heard someone _______ at the door?

A. when; knocking        B. when; knock             C. that; knocking           D. that; knock

24. No computer so far _______ can have the same ability as human brains.

A. be built                    B. having built                     C. being built                D. built

25. _______ Beijing you see today is quite _______ different city from what it used to be.

A. The; 不填               B. The; a                      C. 不填; the                 D. A; a

26. ― It was careless of you _______ your clothes outside all night. 

― My God! ______.

A. to leave; So did I     B. leaving; So do I

C. to have left; So I did D. having left; So do I

27. ― What do you think of the speech?    

― The speaker said _______ nothing worth _______.

A. nearly; listening to   B. hardly; listening

C. scarcely; listening to  D. almost; listening to

28. --I tried to get a hold of Ben last night, but it was so difficult to get through.

--_______. Maybe he was on the Net.

A. That’s probably it    B. That’s strange   C. That’s true D. I know why

29. ― When did he start?     ― He started _______ he got her letter.

A. the moment    B. as long as        C. since        D. until

30. No one would have time to read or listen to an account of everything _______ going on in the world.  

A. it is      B. as is      C. that is   D. what is

31. ― Would you mind _______ me the dictionary? 

― Of course not. But it is ______ my reach.

A. passing; out              B. passing; beyond        C. to pass; far away              D. to pass; out of

32. He was _______ today, but was asked to stay _______ week.

A. to have returned; another   B. returning; one more 

C. returned; another          D. to return; other

33. ―_______ helps others will be helped. 

― So I’ll be thankful to and try to help _______ has helped us.

   A. Whoever; whomever     B. Whoever; whoever 

C. Who; whoever              D. Who; whomever

34. ― Your sister nearly _______ all her spare time to her course during the three years.

   ― That’s right, or she_______ the first place in her school in the 2000 College Entrance Examination.   

A. spent; wouldn’t take    B. devoted; wouldn’t have taken

   C. hadn’t devoted; hadn’t taken  D. hadn’t spent; couldn’t take

35. She’s a teacher, _______ is clear from her manner.

A. that    B. what         C. as       D. who

第二節(jié):完形填空(共20小題;每小題1.5分,滿分30分)

閱讀下面短文,掌握其大意,然后從短文后所給各題的四個(gè)選項(xiàng)(A、B、C和D)中,選出可以填入空白處的最佳選項(xiàng)。

There had been a big battle the day before and our army had taken the enemy's defence works. Night fell and we were in a trench (戰(zhàn)壕) ____36____the enemy had dug as the last ____37____of defence. We could ____38____them digging a new trench ____39____in the distance. And by the morning we could see the ____40____of the spades (鏟子) as they____41____the earth out.

   In our trench, some soldiers ____42____time shooting at the enemy spades to see ____43____they could hit any of them. Then one of the enemy soldiers ____44____our game. He would put his spade up suddenly and ____45____it there for a few seconds to see whether ____46____of us could hit it and then pull it down quickly. ____47____time he would do it in quite a ____48____place. A____49____of our soldiers shot at it ____50____it came up, but none of them ____51____to have hit it. Then there came a time when the spade ____52____down for much longer than ____53____. We thought that the soldier was ____54____from playing the game by an officer. But just ____55____we thought that we could not see the spade again, it came up once more with a bandage (繃帶) tied around it.

36. A. where

B. which

C. since

D. when

37. A. result

B. line

C. moment

D. hope

38. A. watch

B. know

C. hear

D. observe

39. A. themselves

B. ever

C. our enemies

D. our game

40. A. tops

B. colors

C. shapes

D. bottoms

41. A. dug

B. carried   

C. threw

D. stole

42. A. spent

B. wasted  

C. grasped

D. enjoyed

43. A. who

B. if

C. how

D. weather

44. A. attends

B. won

C. joined

D. joined in

45. A. keep

B. kept

C. keeping

D. to keep

46. A. all

B. one

C. none

D. each

47. A. Next

B. Other

C. Last

D. Any

48. A. far

B. strange   

C. different

D. various

49. A. sort

B. kind

C. deal

D. number

50. A. suddenly

B. everywhere

C. only

D. whenever

51. A. honored

B. happened

C. expected

D. seemed

52. A. kept

B. remained

C. taken

D. hid

53. A. always

B. usual

C. the rule

D. their expect

54. A. ordered

B. forced

C. prevented

D. left

55. A. then

B. when

C. a minute

D. now

 

第三部分 閱讀理解 (共20小題; 每小題2分, 滿分40分)

閱讀下列短文, 從每題所給的A、B、C、D 四個(gè)選項(xiàng)中選出最佳選項(xiàng)。

A

The George Washington School had been standing for more than 100 years. The school building was in good shape, but behind it was an old basketball court. The court’s blacktop had been broken and was overgrown with weeds. The fence around the court was battered, and parts of it lay on the ground. The basketball hoops were bent and rusted.

One cold day in February, Mr. Garson, a biology teacher, was taking a walk during his lunch break. He passed the old basketball court. “What an ugly sight!” he said, groaning. As he stared at the empty court, he had a vision. He stopped and let the vision take shape in his imagination. In his mind, he pictured something quite different from what he actually saw.

Mr. Garson asked the school board for money to turn his vision into a reality. In April he organized a group of community volunteers to tear up the old basketball court and take it away. Then he persuaded a local farmer to bring truckloads of good topsoil free of charge, which several students spread over the field. A group of parents volunteered to build a new fence around the land. Mr. Garson bought some garden tools. He also bought seeds and young plants. In May students planted tomatoes, potatoes, corn, lettuce, onions, and peppers. In one place they planted a dozen kinds of flowers that would bloom through the summer and fall.

Two students checked the garden and watered it every day. On Saturdays throughout the summer, groups of students gathered to weed (除草) the garden and harvest what was ripe. In September students enjoyed eating fresh produce from the George Washington garden for lunch. Most days there were freshly cut flowers on the breakfast tables. In late fall a local farmer plowed under the garden so that it would be ready for planting again in the spring.

 “What a beautiful sight!” Mr. Garson announced a speech at the first school assembly. “It proves that we can change things if we work together toward a common goal.”

56. The best title of this passage is _______.

A. What a basketball court!   B. How hard the work is!

C. We need vegetables!       D. What a sight!

57. In this selection, the word “battered” means_______.

A. damaged   B. repaired   C. locked    D. high

58. What is one theme expressed in this selection?

A. It takes a lot of hard work to get large donations.

B. It is important to eat a lot of fresh fruits and vegetables.

C. You shouldn’t be discouraged if you don’t succeed right away.

D. One person with a vision can make a big difference.

59. How does Mr. Garson get topsoil for the garden?

A. He buys it.       B. The school board supplies it.

C. A local farmer donates it.  D. He finds it under the basketball court.

 

B

Creativity(創(chuàng)造性)is the key to a brighter future, say education and business experts. Here is how schools and parents can encourage this important skill in children.

    If Dick Drew had listened to his boss in 1925, we might not have a product that we now think or as of great importance: a new type of tape. Drew worked for the Minnesota Mining Company. At work he developed a kind of material strong enough to hold things together. But his boss told him not to think more about the idea. Finally, using his own time, Drew improved the tape, which now is used everywhere by many people. And his former company learned from its mistake. Now it encourages people to spend 15 percent of their work time just thinking about and developing new ideas.

    Creativity is not something one is just born with, nor is it necessarily a character of high intelligence(智力).The fact that a person is highly intelligent does not mean that he uses it creatively. Creativity is the matter of using the resources one has to produce new ideas that are good for something.

Unfortunately, schools have not tried to encourage creativity. With strong attention to test results and the development of reading, writing and mathematical skills, many educators give up creativity for correct answers. The result is that children can give back information but can't recognize ways to use it in new situations. They may know the rules correctly, but they are unable to use them to work out practical problems.

It is important to give children choices. From the earliest age, children should be allowed to make decisions and understand their results. Even if it's choosing between two food items for lunch, decision-making helps thinking skills. As children grow older, parents should let their children decide how to use their time or spend their money, but not tell them too much if they make the wrong decision. The child may have a hard time, but that is all right. This is because the most important character of creative people is a very strong desire to find a way out of trouble.

60.What did the company where Drew once worked learn from its mistake?

  A. They encouraged people to work a longer time.

B. They discouraged people to think freely.

C. They asked people to spend all their work time developing new ideas.

D. They encouraged people to spend some of their work time considering and improving new ideas.

61. Creativity is something_______.

A. that people are born with       B. that depends on intelligence

C. that is a way of using what one has learned to work out new problems

D. that is not important at all

62.Why don't schools try to encourage creativity?

A. They don't understand the importance of education.

B. They don't want their students to think about anything

  C. They pay too much attention to examination marks, language and mathematical skills.

  D. They think it is very important to remember some information.

63.What should the parents do when their children decide how to spend their money?   A. Try to help them as much as possible

B. Take no notice of whatever they do.

  C. Help them if their decision is wrong, but not too much.

D. Leave them as they are.

 

C

Geologists have been studying volcanoes for a long time. Though they have learned a great deal, they still have not discovered the causes of volcanic action. They know that the inside of the earth is very hot, but they are not sure exactly what causes the great heat. Some geologists have thought that the heat is caused by the great pressure of the earth's outer layers(層). Or the heat may be left from the time when the earth was formed. During the last sixty years scientists have learned about radium, uranium (鈾), thorium, and other radioactive elements(放射性元素). These give out heat all the time as they change into other elements. Many scientists now believe that much of the heat inside the earth is produced by radioactive elements.

Whatever the cause of the heat may be, we do know that the earth gets hotter the farther down we dig. In deep mines and oil wells the temperature rises about 1ㄈ for each 50 feet. At this rate the temperature 40 miles below the earth's surface would be over 4,000. This is much hotter necessary to melt(融化) rock. However, the pressure of the rock above keeps most materials from melting at their usual melting points. Geologists believe that the rock deep in the earth may be plastic, or puttylike. In other words, the rock yields (屈服) slowly to pressure but is not liquid. But if some change in the earth's crust releases the pressure, the rock melts. Then the hot, liquid rock can move up toward the surface.

 When the melted rock works its way close to the earth's crust, a volcano may be formed. The melted rock often contains steam and other gases under great pressure. If the rock above gives way, the pressure is released.

Then the sudden expansion(膨脹) of the gases causes explosion. These blow the melted rock into pieces of different sizes and shoot them high in the air. Here they cool and harden into volcanic ash. Some of the materials fall around the hole made in the earth's surface. The melted rock may keep on rising and pour out as lava. In this way, volcanic ash and lava build up the mountains that we call volcanoes.

64. The main idea of this passage is the _______.

A. interior (內(nèi)部) of the earth   B. formation of volcanoes

   C. results of vocalic action      D. work of geologists

65. The cause for the heat in interior of the earth is_______.

A. radioactive elements     B. the great pressure of the earth

C. not determined   D. the heat remaining from the formation of the earth

66. If the temperature at the earth's surface is 20 ㄈ, the temperature in a coal mine 500 feet below the surface would, in degrees, _______.  

A. 30      B. 40        C. l20    D. 500

 

D

In cars of normal design, the petrol system is made up of three parts: storage tanks, a pump and a carburetor(汽化器).

       The petrol tank is fitted at the back of the car where it is out of the way, yet easily filled at a gas station. Tanks are in various capacity but they usually hold enough petrol for 250~300 miles running. Because the tank is at the opposite end of the car from the carburetor, which is fitted high up on the engine, a pump is needed to draw the petrol from one to the other, as it is from the carburetor that the petrol in finally fed into the engine. Pumps can be of two kinds: electrically operated or mechanically driven from the engine.

67. Which of the following pictures shows the correct petrol system described in this passage?

 

 

 

 

 

 

 

 

68. The text offers the reason why _______.

       A. there are different types of tanks in capacity                           

B. the tank is designed at the back of the car

       C. the pump is mechanically driven from the engine  

D. the petrol is fed into the engine from the carburetor

69. It is necessary to use a pump to send petrol to carburetor because _______.

       A. the engine needs supply with a certain amount of petrol           

B. the pump can press the petrol to recycle

       C. the carburettor has difficulty in drawing petrol from the tank   

D. the tank isn’t fitted in proper position

70. According to the text one tube(管道)of the _______.

       A. pump may be joined to the engine directly                             

B. carburetor may be joined to the engine directly                       

C. tank may be joined to the carburetor directly                          

D. engine may be joined to the tank directly

 

E

Altimeter

    An altimeter is an instrument used in an airplane to tell the pilot how high he is flying.

    The altimeter used in most airplanes is a kind of barometer, which, like barometer found in ordinary homes, is a measuring instrument for air pressure. The weight of the atmosphere presses downwards everywhere. At sea level this pressure is more than 14 pounds on every square inch of the surface. The higher you go into the air, the lower the air pressure is. An altimeter measures this air pressure to show the altitude of the airplane, or, how high it is above sea level.

    But the altimeter does not show how high the plane is above the ground. A plane might be flying at an altitude of 15,000 feet, but it would be only a thousand feet or so above the ground if the land in that area happened to be 14,000 feet above sea level.

    The pilot adjusts his altimeter to the actual sea-level pressure before leaving the airport and then corrects it in flight by new information given to him by radio. He flies high enough to be above any mountain he may pass on his course. The barometer altimeter is correct within about 300 feet.

    Another kind of altimeter, the radio altimeter, makes use of radio reflection. It calculates the height of the flying plane by sending out electrical signals to the surface below and measuring the time required for them to bounce back(反彈). It is correct within 15 feet over water, but is not reliable over land. Big planes usually have both kinds of altimeter.

71. Which of the following diagrams gives the correct relationship between altimeters and barometers? (a--altimeters, b--barometers)

       

72. The following drawing shows a plane flying over a mountain. Which of the heights given in the drawing is given by the barometer altimeter in the plane at this moment?

         

73. The barometer altimeter won’t work if the plane flies______.

A. beyond the atmosphere.        B. above very high land.

C. over very uneven (不平的) ground.   

D. within 1,000 feet of the ground.

74. Suppose a plane using a radio altimeter is flying 10, 000 meters above highland which is 4, 000 meters above sea level. What reading will be given by the altimeter?

    A. 10, 000 meters.               B. 4, 000 meters.  

C. 14, 000 meters.               D. 6, 000 meters

75.Suppose a plane using both kinds of altimeters is flying over a mountainous area where the land rises and falls very abruptly(迅速地). The pilot keeps his plane steady(穩(wěn)定地)at the same height. What kind of reading will you get on each of the altimeters?    

A. The readings on both altimeters will remain steady. 

   B. The readings on both altimeters will rise and fall abruptly.    

C. The readings on the barometer altimeter will rise and fall abruptly, while that on the radio  altimeter will remain steady.

   D. The readings on the radio altimeter will rise and fall abruptly, while that on the barometer altimeter will remain steady.

第二卷。ü35分)

第四部分  寫 作(共兩節(jié),滿分35分)

第一節(jié):任務(wù)型讀寫(共10小題,每小題1分,滿分10分)

閱讀下列短文,根據(jù)所讀內(nèi)容在文章后的表格中填入恰當(dāng)?shù)膯卧~。注意:表格中的每個(gè)空格只填1個(gè)單詞。

Speaking in public is most people’s least favorite thing. The reason is that we are all afraid of making fools of ourselves. The more important the speech is, the more frightened we become.

But stop biting your finger-nails. Public speaking is easy. It’s just plain talking, and you talk all the time. Although I’m basically shy (honest!), I’ve been making speeches and talking on radio and television for more than 30 years, and I can tell you that public speaking is not a “gift” like musical talent. Anybody who can talk can speak in public. Here are some of the lessons I have learned: 

   Your audience is going to come away with one or two of your main ideas. One or two. Not ten or 20. If you can’t express in a sentence or two what you intend to get across, then your speech is not focused well enough. And if you don’t have a clear idea of what you want to say, there’s no way your audience will.

  No matter how long or short your speech is, you’ve got to get your ducks in a row―how you are going to open, what major points you want to make and how you’re going to close.

When I do a radio or TV piece, I often write the last sentence first. When you know where you’re headed, you can choose any route to get there. A strong close is critical: the last thing you say is what your audience will most likely remember.

The standard length of a vaudeville act is usually 12 minutes. If all those performers singing and dancing their hearts out couldn’t go on longer without boring the audience, what makes you think you can?

第二節(jié):書(shū)面表達(dá)(25分):

第二節(jié) 書(shū)面表達(dá)( 滿分25分)

近年來(lái),一些西方節(jié)日在中國(guó)越來(lái)越流行。這種現(xiàn)象在網(wǎng)上引起熱議。請(qǐng)根據(jù)下圖描述中國(guó)人過(guò)洋節(jié)的情況,談?wù)勀銓?duì)這種社會(huì)現(xiàn)象的看法,并將你寫的東西在該英語(yǔ)論壇上發(fā)表。

要求:1. 表達(dá)連貫,邏輯正確。2. 字?jǐn)?shù)150 參考詞匯:情人節(jié):Valentine’s Day

 

Title: How to make a (76)________ speech

Techniques

Reasons

Requirements

 

Keep it simple

You should (77)________ your idea well enough

Prepare one or two of your main ideas.

The audience will not catch your idea if your idea is (78)________.

Get (79)________

You should get your speech well organized.

Know very well about the (81)________, body and ending of the speech

If you don’t, the (80)________ will be confused.

 

Keep it (82)________

Your speech should be short enough to hold your audience curiosity and (83)________.

Make your speech as short as (84)________.

If you don’t, the audience will be (85)________.

 

 

 

 

 

 

 

第一部分 聽(tīng)力:(共20題;每題1.5分;共30分)

1-5 ___  ___  ___  ___  ___       6-10___  ___  ___  ___  ___

11-15___  ___  ___  ___  ___     16-20 ___  ___  ___  ___  ___                      

 

第二部分英語(yǔ)知識(shí)運(yùn)用:          

I單項(xiàng)選擇:

21-25___  ___  ___  ___  ___    26-30___  ___  ___  ___  ___

31-35___  ___  ___  ___  ___

 

II完型填空:(共20小題;每小題1.5分,滿分30分)

36-40___  ___  ___  ___  ___    41-45___  ___  ___  ___  ___

46-50___  ___  ___  ___  ___    51-55 ___  ___  ___  ___  ___                    

 

第三部分 閱讀理解:(共20小題;每小題2分,滿分40分)

56-60___  ___  ___  ___  ___   61-65___  ___  ___  ___  ___

66-70___  ___  ___  ___  ___   71-75___  ___  ___  ___  ___

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

試題詳情

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《數(shù)系的擴(kuò)充與復(fù)數(shù)的引入》

 

試題詳情

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月12日

1.(16分)長(zhǎng)興是我國(guó)最大的蓄電池基地之一,蓄電池是電動(dòng)自行車的核心部件之一,近幾年來(lái)電動(dòng)自行車在長(zhǎng)興城鄉(xiāng)十分普及,極大的方便了居民的出行。下表是一輛電動(dòng)自行車的部分技術(shù)指標(biāo),其中額定車速是指電動(dòng)車滿載情況下在平直道路上以額定功率勻速行駛的速度。

額定

車速

車質(zhì)量

載重

電源

電源輸

出電壓

充電

時(shí)間

額定輸出

功率

電動(dòng)機(jī)額定工作電壓和電流

18 km/h

40 kg

80 kg

36 V/12 AH

≥36 V

6~8 h

180 W

36 V/6A

請(qǐng)參考表中數(shù)據(jù),完成下列問(wèn)題(g取10 m/s2)。

(1)此車所配電動(dòng)機(jī)的內(nèi)阻是多少?

(2)在行駛過(guò)程中電動(dòng)車受阻力是車重(包括載重)的K倍,試計(jì)算K的大小。

(3)若電動(dòng)車滿載時(shí)以額定功率行駛,當(dāng)車速為3 m/s時(shí),加速度為多大?

解:考察電動(dòng)車在滿載且以額定功率勻速行駛時(shí)的情形

(1)P=UI=36×6 W=216 W (2分)

P=180 W,所以P=P-P=36 W (2分)

又P=I2r (1分), 所以r==1 Ω. (1分)

(2)P=Fv (1分) f=kmg (1分)

F=f (1分), 即P=kmgv,故k=0.03. (3分)

(3)由牛頓第二定律可知:a= (2分), 即a=0.2 m/s2. (2分)

2.(20分)如圖所示(a),M、N為中心開(kāi)有小孔的平行板電容器的兩極,相距D=1 m,其右側(cè)為垂直紙面向里的勻強(qiáng)磁場(chǎng),磁感強(qiáng)度B=1×103 T,磁場(chǎng)區(qū)域足夠長(zhǎng),寬為d=0.01 m;在極板M、N之間加有如圖(b)所示的變電壓(設(shè)N極電勢(shì)高于M極時(shí)電壓為正),F(xiàn)有帶負(fù)電粒子不斷從極板M中央小孔處射入電容器內(nèi)(粒子的初速度可看做為零,重力不計(jì)),取其荷質(zhì)比=2×1011 C/kg,問(wèn):

(1)在變交電壓第一個(gè)周期內(nèi)哪些時(shí)刻進(jìn)入電容器內(nèi)的粒子能從磁場(chǎng)的右側(cè)射出來(lái)?

(2)若上述交變電壓的周期可以變化,則其周期滿足什么條件時(shí),才能保證有帶電粒從右側(cè)射出來(lái)?

解:(1)粒子要從磁場(chǎng)的右側(cè)射出,它做圓周運(yùn)動(dòng)的半徑須滿足

r≥d。(2分)

又r= (3分)

得v> (1分)

粒子在電場(chǎng)中,無(wú)論做加速運(yùn)動(dòng)還是做減速運(yùn)動(dòng),其加速度都為:

a=? (2分)

設(shè)帶電粒子先做加速運(yùn)動(dòng)后做減速運(yùn)動(dòng)至極板N在中央小孔處,以速度v進(jìn)入磁場(chǎng)中,則:

D=+ (4分)

式中t為粒子做加速運(yùn)動(dòng)的時(shí)間,得:

t= 2分

代人數(shù)據(jù)得:t≥0.61×106 s (2分)

所以在0~0.39×106s時(shí)間內(nèi)進(jìn)入電容器內(nèi)的粒子將從磁場(chǎng)右側(cè)射出。 (1分)

(2)由以上分析可知,帶電粒子加速運(yùn)動(dòng)的時(shí)間至少為0.61×106 s,則

≥0.61×106 s (2分)

即T≥1.22×106 s。(1分)

 

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月13日

3.(16分)如圖所示,AB為豎直墻壁,空間存在著豎直向下的勻強(qiáng)電磁,F(xiàn)將一質(zhì)量為m的帶正電小球在距墻為l的P點(diǎn)以水平速度v向右拋出,球打在墻上的C點(diǎn)。現(xiàn)撤去電場(chǎng),使球在距墻為2l的Q點(diǎn)仍以水平速度v向右拋出(P、Q在同一水平線上),結(jié)果球仍打在墻上的C點(diǎn)。由此可知,小球所受的電場(chǎng)力是重力的多少倍?

 

4. (18分) 如圖所示,半徑為r的閉合圓環(huán)由質(zhì)量為m、電阻為R的細(xì)金屬絲制成,圓環(huán)水平放置在兩磁極的狹縫間,輻向分布的磁場(chǎng)僅存在于圓筒形磁極S和圓柱形磁極N之間,圓環(huán)平面與磁場(chǎng)方向平行,圓環(huán)所在處的磁感應(yīng)強(qiáng)度大小為B。圓環(huán)從靜止開(kāi)始釋放(不計(jì)空氣阻力),其平面在下落過(guò)程中始終保持水平。

    (1)求圓環(huán)下落的最大速度vm(設(shè)磁場(chǎng)區(qū)域在豎直方向足夠長(zhǎng));

    (2)當(dāng)圓環(huán)下落的加速度為g/2時(shí),求圓環(huán)的發(fā)熱功率P;

    (3)已知圓環(huán)下落時(shí)間為T時(shí),下落高度為H,其速度為v0(v0<vm=。若在該時(shí)間T內(nèi),圓環(huán)內(nèi)產(chǎn)生的熱量與一恒定電流I0在該圓環(huán)內(nèi)產(chǎn)生的熱量相同,求恒定電流I0的表達(dá)式。

         

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月14日

 

 

5.(20分) 如圖所示,傾角θ=30°的光滑斜面的底端固定著一個(gè)垂直于斜面的擋板,斜面上有一根勁度系數(shù)為k=100N/m的輕質(zhì)彈簧,其兩端分別焊接著質(zhì)量為mB=mC=4kg的B、C兩個(gè)小球,B球處于靜止?fàn)顟B(tài)且彈簧壓縮量為x。今另有一質(zhì)量為mA= 1kg的A球從距B球2x的D 點(diǎn)以初速度v0=m/s 沿斜面滑下, A、B兩球碰撞后,A球沿斜面向上運(yùn)動(dòng)且恰好能回到D點(diǎn),此時(shí)取走A球。(g=10m/s2)求:

    (1) B球靜止時(shí)彈簧的壓縮量x;

    (2) A球下滑2x即將與B球碰撞時(shí)的速度v1的大。

(3) 試推算C球能否被拉離擋板。

6、(16分)如圖所示,以O(shè)為原點(diǎn)建立直角坐標(biāo)系Oxy,絕緣光滑水平面沿著x軸,y軸在豎直方向。在水平面上方存在與x軸平行的勻強(qiáng)電場(chǎng)。一個(gè)質(zhì)量m = 2.0×10-3kg、電量q = 2.0×10-6C的帶正電的物體(可作為質(zhì)點(diǎn)),從O點(diǎn)開(kāi)始以一定的初速度沿著x軸正方向做直線運(yùn)動(dòng),其位移隨時(shí)間的變化規(guī)律為x = 6.0 t -10 t 2,式中x的單位為m,t的單位為s。不計(jì)空氣阻力,取g =10m/s2。

(1)求勻強(qiáng)電場(chǎng)的場(chǎng)強(qiáng)大小和方向;

(2)求帶電物體在0.5s內(nèi)經(jīng)過(guò)的路程;

(3)若在第0.6s末突然將勻強(qiáng)電場(chǎng)的方向變?yōu)檠?

y軸正方向,場(chǎng)強(qiáng)大小保持不變。求在0~0.8s

內(nèi)帶電物體電勢(shì)能的變化量。

解:(1)(4分)加速度大小  a = 20m/s2             (1分)

            根據(jù)牛頓第二定律  Eq = ma         (1分)

            解得場(chǎng)強(qiáng)    E = 2.0×104N/C         (1分)

                        方向沿x軸負(fù)方向      (1分)

(2)(6分)物體在O點(diǎn)的初速度    v0 = 6.0m/s   (1分)    

減速時(shí)間    t1 =  = 0.3s          (1分)

0.3s內(nèi)經(jīng)過(guò)的路程  x1 = = 0.9 m  (1分)

            后0.2s物體做勻加速直線運(yùn)動(dòng),經(jīng)過(guò)的路程

                                x2 = = 0.4m     (1分)

0.5s內(nèi)物體經(jīng)過(guò)的路程   s = x1+x2 = 1.3m    (2分)

(3)(6分)第0.6s末帶電物體回到坐標(biāo)原點(diǎn)O          (1分)

之后的0.2s物體以初速度v0做類平拋運(yùn)動(dòng)

            在y方向根據(jù)牛頓第二定律

                  Eq ? mg = ma′  (1分)

                        (1分)

             解得物體在y方向經(jīng)過(guò)的距離y0 = 0.2m  (1分)

             電場(chǎng)力做功  W = Eq y0 = 8.0×10-3J      (1分)

             所以電勢(shì)能減少8.0×10-3J            (1分)

             (或電勢(shì)能的變化量為 ∆EP = ? 8.0×10-3J)

 

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月14日

 

 

(1)人從斜坡上滑下的加速度為多大?

(2)若AB的長(zhǎng)度為25m,人滑到B處時(shí)速度為多大?

(3)若AB的長(zhǎng)度為25m,求BC的長(zhǎng)度為多少?

解:(1)設(shè)人斜坡上滑下的加速度為,由牛頓第二定律有

                                      ①(1分)

                                                                         ②(1分)

                                                                                    ③(1分)

    聯(lián)立①②③式得                                 ④(1分)

    代入數(shù)據(jù)得                                                        (2分)

   (2)人滑到B點(diǎn)時(shí)                            ⑤(3分)

   (3)在水平軌道上運(yùn)動(dòng)時(shí)                                        ⑥(1分)

                                                     ⑦(1分)

聯(lián)立⑥⑦式得                                                    ⑧(2分)

                                      ⑨(2分)

聯(lián)立⑤⑧⑨式得                            (1分)

8.(18分)如圖12所示,豎直平面xOy內(nèi)存在水平向右的勻強(qiáng)電場(chǎng),場(chǎng)強(qiáng)大小E=10N/c,在y≥0的區(qū)域內(nèi)還存在垂直于坐標(biāo)平面向里的勻強(qiáng)磁場(chǎng),磁感應(yīng)強(qiáng)度大小B=0.5T。一帶電量q=+0.2C、質(zhì)量m=0.4kg的小球由長(zhǎng)L=0.4m的細(xì)線懸掛于P點(diǎn)小球可視為質(zhì)點(diǎn),現(xiàn)將小球拉至水平位置A無(wú)初速度釋放,小球運(yùn)動(dòng)到懸點(diǎn)P正下方的坐標(biāo)原點(diǎn)O時(shí),懸線突然斷裂,此后小球又恰好能通過(guò)O點(diǎn)正下方的N點(diǎn)。(g=10m/s222),求:

(1)小球運(yùn)動(dòng)到O點(diǎn)時(shí)的速度大;

(2)懸線斷裂前瞬間拉力的大。

(3)ON間的距離。

 

解:(1)小球從A運(yùn)到O的過(guò)程中,根據(jù)動(dòng)能定理:

                                                                                      ①(3分)

則得小球在O點(diǎn)速度為:

                                                    ②(3分)

(2)小球運(yùn)動(dòng)到O點(diǎn)懸線斷裂前瞬間,對(duì)小球運(yùn)用牛頓第二定律:

                                                                 ③(2分)

                                                                              ④(1分)

由③④得:                              ⑤(3分)

(3)懸線斷后,小球水平方向加速度

                                                             ⑥(2分)

小球從O點(diǎn)運(yùn)動(dòng)至N點(diǎn)所用時(shí)間

                                                                        ⑦(2分)

ON間距離

                     ⑧(2分)

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月16日

 

 

 

文本框:  9.(20分)如圖13甲所示,一邊長(zhǎng)L=2.5m、質(zhì)量m=0.5kg的正方形金屬線框,放在光滑絕緣的水平面上,整個(gè)裝置放在方向豎直向上、磁感應(yīng)強(qiáng)度B=0.8T的勻強(qiáng)磁場(chǎng)中,它的一邊與磁場(chǎng)的邊界MN重合。在水平力F作用下由靜止開(kāi)始向左運(yùn)動(dòng),經(jīng)過(guò)5s線框被拉出磁場(chǎng)。測(cè)得金屬線框中的電流隨時(shí)間變化的圖像如乙圖所示,在金屬線框被拉出的過(guò)程中。

(1)求通過(guò)線框?qū)Ь截面的電量及線框的電阻;

(2)寫出水平力F隨時(shí)間變化的表達(dá)式;

(3)已知在這5s內(nèi)力F做功1.92J,那么在此過(guò)程中,線框產(chǎn)生的焦耳熱是多少?

解:(1)根據(jù)                                                   (3分)

又根據(jù)                                                    (3分)

    得                                                                              (4分)

(2)由電流圖像可知,感應(yīng)電流隨時(shí)間變化的規(guī)律:I=0.1t    (2分)

由感應(yīng)電流可得金屬框的速度隨時(shí)間也是線性變化的,

                                                                       (3分)

線框做勻加速直線運(yùn)動(dòng),加速度                        (1分)

線框在外力F和安培力FA作用下做勻加速直線運(yùn)動(dòng),

F-FA=ma                                                                                 (1分)

得力F=(0.2t+0.1)N

(3)t=5s時(shí),線框從磁場(chǎng)中拉出時(shí)的速度v5=at=1m/s  (2分)

線框中產(chǎn)生的焦耳熱  (2分)

高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。10.(15分)如圖8所示,在光滑絕緣的水平桌面上放有四分之一圓弧槽AB,其中虛線OA、OB為圓弧槽的兩條半徑。沿水平方向有勻強(qiáng)電場(chǎng),電場(chǎng)方向與OB平行。有一質(zhì)量為m、電荷量為q的小球,以初速度高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。沿OA方向從O點(diǎn)出發(fā),經(jīng)過(guò)一段時(shí)間第一次碰到圓弧槽,碰撞點(diǎn)恰好在圓弧槽AB的中點(diǎn)C處,求:A、B兩點(diǎn)間的電勢(shì)差?

解:帶電小球在電場(chǎng)中做類平拋運(yùn)動(dòng),設(shè)圓弧半徑為R。

據(jù)題意:

Rsin45°= v0t                                                                                                         (3分)

Rcos45°=  at2                                                                       (3分)

其中a =                                                                               (3分)

在勻強(qiáng)電場(chǎng)中:E =                                                          (3分)

上式聯(lián)立解得:UAB =                                             (3分)

(其它解法只要合理同樣得分)

 

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月17日

 

高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。

 

11.(18分)有一顆地球衛(wèi)星,繞地球做勻速圓周運(yùn)動(dòng)

衛(wèi)星與地心的距離為地球半徑高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。的2倍,衛(wèi)星圓

形軌道平面與地球赤道平面重合。衛(wèi)星上的太陽(yáng)能

收集板可以把光能轉(zhuǎn)化為電能,太陽(yáng)能收集板的面

積為高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。,在陽(yáng)光下照射下每單位面積提供的最大電

功率為高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。。已知地球表面重力加速度為高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。,近似認(rèn)

為太陽(yáng)光是平行光,試估算太陽(yáng)能收集板在衛(wèi)星繞

地球一周的時(shí)間內(nèi)最多轉(zhuǎn)化的電能?

解:地球衛(wèi)星做勻速圓周運(yùn)動(dòng),根據(jù)牛頓第二定律:

高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。= m(2R0)                                                                               (4分)

在地球表面有: = m′g                                                                       (4分)

∴衛(wèi)星做勻速圓周運(yùn)動(dòng)的周期為:

T = 4π                                                                                             (2分)

如圖,當(dāng)衛(wèi)星在陰影區(qū)時(shí)不能接受陽(yáng)光,據(jù)幾何關(guān)系:

∠AOB = ∠COD =                                           (2分)

∴衛(wèi)星繞地球一周,太陽(yáng)能收集板工作時(shí)間為:

t =  T                                                                                     (2分)

最多轉(zhuǎn)化的電能:

E = PSt =                                                                              (4分)

高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。12.(21分)如圖10所示,勻強(qiáng)磁場(chǎng)區(qū)下邊界是水平地面,上邊界與地面平行,相距高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。=1.0m,兩個(gè)正方形金屬線框高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。在同一豎直平面內(nèi),與磁場(chǎng)方向始終垂直。高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。的下邊框與地面接觸,上邊框與絕緣輕線相連,輕線另一端跨過(guò)兩個(gè)定滑輪連著線框高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。。同時(shí)靜止釋放高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。,發(fā)現(xiàn)高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。全部離開(kāi)磁場(chǎng)時(shí),高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。還未進(jìn)入磁場(chǎng),而且當(dāng)線框P整體經(jīng)過(guò)磁場(chǎng)區(qū)上邊界時(shí),一直勻速運(yùn)動(dòng),當(dāng)線框Q整體經(jīng)過(guò)磁場(chǎng)區(qū)上邊界時(shí),也一直勻速運(yùn)動(dòng)。若線框P的質(zhì)量高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。、邊長(zhǎng)高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。、總電阻高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。,線框Q的質(zhì)量高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。、邊長(zhǎng)高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。、總電阻高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。忽略一切摩擦和空氣阻力,重力加速度高考資源網(wǎng)( www.ks5u.com),中國(guó)最大的高考網(wǎng)站,您身邊的高考專家。。求:

   (1)磁感應(yīng)強(qiáng)度的大。

   (2)上升過(guò)程中線框P增加的機(jī)械能的最大值?

解:(1)線框P在磁場(chǎng)中,P上升,Q下落,二者機(jī)械能守恒:

(m2-m1)g(h-L1)= 12(m1+m2)v12                                                   (3分)

線框P經(jīng)過(guò)磁場(chǎng)區(qū)上邊界時(shí):m2g = m1g+                                      (3分)

解得:B =  T≈ 3.33T         v1 = 2m/s                                                               (3分)

(2)從線框P完全離開(kāi)磁場(chǎng)到線框Q開(kāi)始進(jìn)入磁場(chǎng),二者機(jī)械能守恒:

(m2-m1)g(H-h(huán))= (m1+m2)v22-(m1+m2)v12                       (3分)

線框Q經(jīng)過(guò)磁場(chǎng)區(qū)上邊界時(shí):m2g = m1g+                                      (3分)

解得:H = 1.5m           v2 = 3m/s

線框Q完全進(jìn)入磁場(chǎng)后到落地前,二者機(jī)械能守恒:

(m2-m1)g(h-L2)= (m1+m2)v32-(m1+m2)v22                      (3分)

解得:v3 = 4m/s

線框P增加的機(jī)械能ΔE = 12m1v32+m1g(H+h)= 3.3J                                      (3分)

2009最新全國(guó)各地高考模擬題計(jì)算題(考前每日兩題)匯編(05月18日

 

 

 

13.(16分)如圖甲所示,一質(zhì)量為2.0kg的物體靜止在水平面上,物體與水平面間的動(dòng)摩擦因數(shù)為0.20。從t=0時(shí)刻起,物體受到水平方向的力F的作用而開(kāi)始運(yùn)動(dòng),8s內(nèi)F隨時(shí)間t變化的規(guī)律如圖乙所示。求:(g取10m/s2

   (1)4s末物體速度的大小;

   (2)在圖丙的坐標(biāo)系中畫出物體在8s內(nèi)的v ? t 圖象;(要求計(jì)算出相應(yīng)數(shù)值)

 

 

 

 

 

 

 

 

 

解:(1)(6分)物體受到水平力F和摩擦力的作用

設(shè)加速度為,4s末速度為,由牛頓第二定律

          (2分)

          (2分)

          (2分)

   (2)(6分)由圖知,在4―85s內(nèi),物體受到水平力F的大小不變,

       方向改變,設(shè)加速度為,5s末速度為

      

           (1分)

          (1分)

       由圖知,5―8s內(nèi)物體只受摩擦力作用,設(shè)加速度為,速度為

      

           (1分)

      

       在t=7.5s時(shí)物體停止運(yùn)動(dòng),   (1分)

       物體運(yùn)動(dòng)的v-t圖像如圖所示        (2分)

   (3)(4分)由v-t圖可知(或計(jì)算得出)

       0―4s內(nèi)   (1分)

       4―5s內(nèi)   (1分)

       水平力F做功   (1分)

       得    (1分)

 

 

 

 

14.

      金屬框垂直軌道的邊長(zhǎng),兩磁場(chǎng)的寬度均與

      金屬框的邊長(zhǎng)相同,金屬框整個(gè)回路的電阻

      ,g取10m/s2。假如主鳳計(jì)要求電梯以

      的速度勻速上升,求:

         (1)金屬框中感應(yīng)電流的大小及圖示時(shí)刻感應(yīng)電流的方向;

         (2)磁場(chǎng)向上運(yùn)動(dòng)速度

       

       

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