分析:利用基本初等函數(shù)的導(dǎo)數(shù)公式、導(dǎo)數(shù)的運(yùn)算法則對(duì)給出的四種運(yùn)算逐一驗(yàn)證,即可得到正確答案.
解答:解:因?yàn)?span id="9lj4opd" class="MathJye">(x+
)′=
x′+(
)′=1-
,所以選項(xiàng)A不正確;
(log2x)′=,所以選項(xiàng)B正確;
((2x+3)
2)
′=2(2x+3)•(2x+3)
′=4(2x+3),所以選項(xiàng)C不正確;
(e
2x)
′=e
2x•(2x)
′=2e
2x,所以選項(xiàng)D不正確.
故選B.
點(diǎn)評(píng):本題考查了簡(jiǎn)單的復(fù)合函數(shù)的導(dǎo)數(shù),解答的關(guān)鍵是熟記基本初等函數(shù)的導(dǎo)數(shù)公式,對(duì)于復(fù)合函數(shù)的求導(dǎo),復(fù)合函數(shù)y=f(g(x))的導(dǎo)數(shù)和y=f(u),u=g(x)的導(dǎo)數(shù)間的關(guān)系是yx′=yu′•ux′,此題是基礎(chǔ)題.