考點:合數(shù)與質(zhì)數(shù),奇數(shù)與偶數(shù)的初步認識
專題:數(shù)的整除
分析:兩個質(zhì)數(shù)的乘積一定是含有這兩個質(zhì)數(shù)、1,它們的乘積4個因數(shù),所以是合數(shù);兩個偶數(shù)的乘積一定是2的倍數(shù),所以一定是偶數(shù);由此解答即可.
解答:
解:由分析可知:兩個質(zhì)數(shù)的乘積一定是 合數(shù),兩個偶數(shù)的乘積一定是 偶數(shù);
故答案為:合數(shù),偶數(shù).
點評:解答此題應(yīng)明確:只有1和它本身兩個約數(shù)的數(shù)是質(zhì)數(shù),除了1和它本身還有別的約數(shù)的數(shù)是合數(shù),是2的倍數(shù)的數(shù)是偶數(shù),不是2的倍數(shù)的數(shù)是奇數(shù).