Question

計(jì)算下列各題
（1）計(jì)算(3

3

8

)-  

2

3

-(

2

-1)0+

23-6 ( 2 -2)2

-(2

2

)

1

3

（2）計(jì)算

lg5•lg8000+(lg2 3 )2

(log23+log49+log827+…+log2n3n)×log9 n 64

．

Answer 1

分析：（1）利用指數(shù)冪的運(yùn)算性質(zhì)即可求出；
（2）利用對(duì)數(shù)的運(yùn)算性質(zhì)即可求出．

解答：解：（1）原式=[(

2

3

)-3]-

2

3

-1+

23-6(2- 2 )

-(2

3

2

)

1

3

=

4

9

-1+

11+2 18

-

2

=

4

9

-1+

9

+

2

-

2

=

22

9

；
（2）原式=

lg5(3+3lg2)+3(lg2)2

(log23+log23+…+log23)× 1 2 log32 6 n

=

3lg5+3lg2(lg5+lg2)

nlog23× n 12 log32

=

3

n2 12

=

n2

36

點(diǎn)評(píng)：本題主要考查有理指數(shù)冪的運(yùn)算法則和對(duì)數(shù)的運(yùn)算法則，學(xué)習(xí)中應(yīng)當(dāng)做到非常熟練．