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id="move-animate-left"> <li id="cdiid0j" class="current"><a href="javascript:void(0);" id="shitilink">試題答案</a></li> <li style="display:none"><a href="javascript:void(0);" id="daanlink">練習冊答案</a></li> <li><a href="javascript:void(0);" id="kechenglink">在線課程</a></li> </ul> <div id="ksaylax" class="tabcon"> <div id="c0zuf3t" class="subbox"> <div id="8se4hfa" class="sublist" style="display:block"> <div id="rwfnxoj" class="answer_inner" style="display:block"> 【答案】<em>分析：</em>解決此題要知道電磁波的傳播速度和光速一樣，速度值等于3×10<sup>8</sup>m/s，超聲是頻率超過20000Hz的聲音，具有很強的穿透能力．<br><em>解答：</em>解：電磁波的傳播速度和光速一樣，速度值等于3×10<sup>8</sup>m/s，雷達探測儀能穿透很厚的雪層，所以要有很強的穿透能力，因此它利用的是超聲波；<br>故答案為：3×10<sup>8</sup>m/s，超聲波．<br><em>點評：</em>電磁波的傳播速度和光速一樣，超聲是頻率超過20000Hz的聲音，具有很強的穿透能力，要會用這些知識點解決實際問題． </div> </div> <div id="sdzrjuj" class="sublist"><div id="znmk8st" class="answer_inner pic-group"><img src="http://thumb.zyjl.cn/images/loading.gif"></div></div> <div id="cliotb9" class="sublist"><div id="rpx9gnb" class="answer_inner"><img 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class="source">初中物理</span> <strong>來源：</strong><span id="2jh1hti" class="source"></span> <strong>題型：</strong><span id="u58nusa" class="source"></span> </p> <div id="cswythc" class="xtq"><div><div id="rjszndz" class="motable">2005年5月22日，我國登山測量隊員攜帶先進儀器成功登頂珠峰．所帶的GPS，表示<!--BA--><div id="hhkjc2x" class="quizPutTag">全球衛(wèi)星定位系統(tǒng)</div><!--EA--><div id="j3tltoc" class="sanwser">全球衛(wèi)星定位系統(tǒng)</div>，可通過電磁波在地面和衛(wèi)星之間傳遞信息．利用衛(wèi)星通信，可以使人們的通信更加的便捷．地球同步通信衛(wèi)星在赤道平面上距地球表面高為3.6×10<sup>7</sup>m的軌道上．一般只要有<!--BA--><div id="zy8xlhj" class="quizPutTag">3</div><!--EA--><div id="kqvjzb5" class="sanwser">3</div>顆互成<!--BA--><div id="rw5pveo" class="quizPutTag">120</div><!--EA--><div id="re8ptsb" class="sanwser">120</div>度角的同步衛(wèi)星，就可以覆蓋幾乎整個地球．登山測量隊員所帶的雷達探測儀能利用<!--BA--><div id="4cznw90" class="quizPutTag">超聲波</div><!--EA--><div id="eemt1zy" class="sanwser">超聲波</div>來探測山項冰雪的厚度（選填“超聲波”或“次聲波”）．</div></div></div> <p class="bottom"> </p> <a 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