解:(1)原式=
-
=
;
(2)原式=7+9
=16
;
(3)(-4
)+(+3
)
=-(4
-3
)
=-1
=-1
;
(4)(-
)-(-3
)
=(-
)+(+3
)
=3
-
=2
;
(5)(-3.7)-
=(-3.7)+(-0.3)
=-4;
(6)
-
=
-
=
;
(7)(3-9)-(4-8)
=-6-(-4)
=(-6)+(+4)
=-2;
(8)(-
)+(+
)+(+
)+(-1
)
=(-
)+(-1
)+(+
)+(+
)
=-2+1
=-1;
(9)-(-3
)-(+
)-(-2
)
=3
-
+2
=5
-
=5
-
=5
;
(10)(-36.35)+(-7.25)+26.35+(+7
)+10
=(-36.35)+26.35+(-7.25)+(+7.25)+10
=-10+10
=0;
(11)2
+(-2
)+(-1
)+4
+(-1
)+(-3
)
=2
+4
+(-2
)+(-1
)+(-1
)+(-3
)
=7-4-5
=-2;
(12)|
-1|+|
-
|+|
-
|+|
-
|+…|
-
|
=1-
+
-
+
-
+…+
-
=1-
=
.
分析:(1)根據有理數(shù)的加法法則通分后相加即可;
(2)去掉絕對值符號后相加即可;
(3)根據有理數(shù)的加法法則通分后相加即可;
(4)先化成加法,再根據有理數(shù)的加法法則進行計算即可;
(5)把分數(shù)變成小數(shù),再相加即可;
(6)通分后相減即可;
(7)先算括號內的,再相減即可;
(8)把分母相同的相加,再進行加法求出即可;
(9)先把減法變成加法,再根據有理數(shù)的加法法則計算即可;
(10)把相加為整數(shù)和互為相反數(shù)的加數(shù)相加,再求出即可;
(11)把分母相同的相加,再進行加法求出即可;
(12)先去絕對值符號,再合并,最后計算求出即可.
點評:本題考查了有理數(shù)的加減混合運算,主要考查學生的計算能力.