16.計(jì)算
(1)7xy-2(4xy-3)
(2)先化簡(jiǎn),再求值:-2x2-$\frac{1}{2}$[2y2-2(x2-y2)+6],其中x=-1,y=-$\frac{1}{2}$.

分析 (1)原式去括號(hào)合并即可得到結(jié)果;
(2)原式去括號(hào)合并得到最簡(jiǎn)結(jié)果,把x與y的值代入計(jì)算即可求出值.

解答 解:(1)原式=7xy-8xy+6=-xy+6;
(2)原式=-2x2-y2+x2-y2-3=-x2-2y2-3,
當(dāng)x=-1,y=-$\frac{1}{2}$時(shí),原式=-1-$\frac{1}{2}$-3=-4$\frac{1}{2}$.

點(diǎn)評(píng) 此題考查了整式的加減-化簡(jiǎn)求值,熟練掌握運(yùn)算法則是解本題的關(guān)鍵.

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