分析:本題中分子、分母中的除法算式中的數(shù)據(jù)具有倍數(shù)關(guān)系,所以可將分子分母分別分解進(jìn)行計(jì)算,然后再找出數(shù)據(jù)中的聯(lián)系進(jìn)行巧算.分子=2÷3÷7+(2×2)÷(3×2)÷(7×2)+(2×7)÷(3×7)÷(7×7);分母=4÷7÷9+(4×2)÷(7×2)÷(9×2)+(4×7)÷(7×7)÷(9×7),由此據(jù)分配律進(jìn)行巧算即可.
解答:解:
2÷3÷7+4÷6÷14+14÷21÷49 |
4÷7÷9+8÷14÷18+ 28÷ 49÷63 |
=[2÷3÷7+(2×2)÷(3×2)÷(7×2)+(2×7)÷(3×7)÷(7×7)]÷[4÷7÷9+(4×2)÷(7×2)÷(9×2)+(4×7)÷(7×7)÷(9×7)],
=[2÷3÷7+
×(2÷3÷7)+
×(2÷3÷7)]÷[4÷7÷9+
×(4÷7÷9)+
×(4÷7÷9)],
=[(1+
+
)×(2÷3÷7)]÷[(1+
+
)×(4÷7÷9)],
=(2÷3÷7)÷(4÷7÷9),
=
÷,
=
.
故答案為:
.
點(diǎn)評(píng):完成本題要認(rèn)真分析式中數(shù)據(jù),找出其內(nèi)在聯(lián)系然后再進(jìn)行巧算.