Question

3．被減數(shù)、減數(shù)、差的和是$\frac{11}{15}$，減數(shù)是差的1$\frac{1}{5}$ 倍，減數(shù)是$\frac{1}{5}$．

Answer 1

分析 根據(jù)題意，可知被減數(shù)+減數(shù)+差=$\frac{11}{15}$，被減數(shù)=減數(shù)+差，即2×（減數(shù)+差）=$\frac{11}{15}$，又減數(shù)是差的1$\frac{1}{5}$ 倍，差=減數(shù)÷1$\frac{1}{5}$，代入即可．

解答 解：被減數(shù)+減數(shù)+差=$\frac{11}{15}$
減數(shù)+差+建數(shù)+差=$\frac{11}{15}$
2×（減數(shù)+差）=$\frac{11}{15}$
減數(shù)+差=$\frac{11}{30}$
減數(shù)+減數(shù)÷1$\frac{1}{5}$=$\frac{11}{30}$
$\frac{11}{6}$減數(shù)=$\frac{11}{30}$
減數(shù)=$\frac{1}{5}$
答：減數(shù)是$\frac{1}{5}$．
故答案為：$\frac{1}{5}$．

點(diǎn)評(píng) 解答本題關(guān)鍵是明確：被減數(shù)=減數(shù)+差，把原式化成只含減數(shù)和差的式子．