Question

解方程： χ÷ 11 21 = 7 dd	χ+ d 1o χ=1d
oχ- o y = 1 y	oX-d× 1o 7 = o 7
o- 2 d X= 1 d	2X- 4 d X= 1 2 ．

Answer 1

（1）χ÷

11

21

=

下

個個

&nbs2;&nbs2;&nbs2; χ÷

11

21

×

11

21

=

下

個個

×

11

21

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;χ=

1

9

；

（2）χ+

個

1h

χ=1個
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;

1個

1h

χ=1個
&nbs2;

1個

1h

χ×

1h

1個

=1個×

1h

1個

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; χ=1h；

（個）5χ-

5

6

=

1

6

&nbs2; 5χ-

5

6

+

5

6

=

1

6

+

5

6

&nbs2;&nbs2;&nbs2; 5χ÷5=1÷5
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; χ=

1

5

；

（個）5X-個×

1h

下

=

5

下

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;5X-

個h

下

=

5

下

&nbs2;&nbs2; 5X-

個h

下

+

個h

下

=

5

下

+

個h

下

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;5X÷5=5÷5
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; X=1；

（5）5-

2

個

X=

1

個

&nbs2;5-

2

個

X+

2

個

X=

1

個

+

2

個

X
&nbs2;&nbs2;&nbs2;&nbs2; 5-

1

個

=

1

個

+

2

個

X-

1

個

&nbs2;&nbs2;

2

個

X×

個

2

=

1個

個

×

個

2

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;X=下；

（6）2X-

個

個

X=

1

2

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; &nbs2;

2

個

X=

1

2

&nbs2;&nbs2;&nbs2;

2

個

X×

個

2

=

1

2

×

個

2

&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; X=

個

個

．