Question

如圖是一個(gè)風(fēng)箏的圖案，它是軸對(duì)稱(chēng)圖形，量得∠B=30°，則∠E的大小為（　�。�

A．30°

B．35°

C．40°

D．45°

Answer 1

分析：由已知條件，根據(jù)軸對(duì)稱(chēng)圖形的性質(zhì)解答．

解答：解：因?yàn)椤螧與∠E是對(duì)應(yīng)角，∠B=30°，AF為對(duì)稱(chēng)軸，
所以∠E=∠B=30°．
故選A．

點(diǎn)評(píng)：本題考查了軸對(duì)稱(chēng)的性質(zhì)；軸對(duì)稱(chēng)圖形是按一條直線折疊后兩邊重合的圖形，題中圖形對(duì)稱(chēng)軸為AF，B點(diǎn)對(duì)稱(chēng)點(diǎn)為E點(diǎn)，找準(zhǔn)對(duì)應(yīng)點(diǎn)是解題的關(guān)鍵．