Question

9．甲、乙、丙三名同學(xué)到果園摘桃子，甲同學(xué)摘的桃子個數(shù)比乙同學(xué)多$\frac{1}{5}$，乙同學(xué)摘的桃子個數(shù)比丙同學(xué)多$\frac{1}{5}$，甲同學(xué)摘的桃子個數(shù)比丙同學(xué)多幾分之幾？

Answer 1

分析 設(shè)丙同學(xué)摘的桃子個數(shù)為單位“1”，則乙同學(xué)摘的桃子個數(shù)為1+$\frac{1}{5}$，甲同學(xué)摘的桃子個數(shù)為（1+$\frac{1}{5}$）×（1+$\frac{1}{5}$），再用甲同學(xué)摘的桃子個數(shù)減丙同學(xué)摘的桃子個數(shù)即可．

解答 解：（1+$\frac{1}{5}$）×（1+$\frac{1}{5}$）-1
=$\frac{6}{5}×\frac{6}{5}$-1
=$\frac{36}{25}$-1
=$\frac{11}{25}$，
答：甲同學(xué)摘的桃子個數(shù)比丙同學(xué)多$\frac{11}{25}$．

點評 本題考查了分?jǐn)?shù)四則復(fù)合應(yīng)用題，關(guān)鍵是得出甲同學(xué)摘的桃子個數(shù)為（1+$\frac{1}{5}$）×（1+$\frac{1}{5}$）．求一個數(shù)是另一個數(shù)的幾分之幾，用除法計算．