Question

曲線y=x²-1與y=1-x³在點(diǎn)x=x₀處的切線既不互相平行也不互相垂直，則x₀的取值范圍是

A.{x∈R|x≠-且x≠0且x≠}               B.{x∈R|x≠且x≠}

C.{x∈R|x≠且x≠0且x≠}                 D.{x∈R|x≠-且x≠}

Answer 1

A?

解析:y₁=x²-1,y₂=1-x³,y₁′=2x,y₂′=-3x².?

∵在x=x₀處切線既不平行又不垂直,?

∴2x₀≠-3x₀²,?

且2x₀(-3x₀²)≠-1.?

∴x₀≠0且x₀≠-,且x₀≠.選A.