已知在銳角
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中,
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為角
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所對的邊,且
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.
(1)求角
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的值;
(2)若

,則求

的取值范圍.
(1)
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;(2)

.
試題分析:(1)先根據(jù)正弦定理將等式
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中的邊換成角,進而根據(jù)余弦的二倍角公式、兩角和與差公式進行化簡得到
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,進而得到
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,結合
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角的范圍即可得到

的值;(2)根據(jù)正弦定理,將邊轉化成角即

,進而根據(jù)三角形的內角和將其中的一個角換掉得到
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,然后根據(jù)題中條件確定
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的取值范圍:
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,然后得到
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,進而根據(jù)三角函數(shù)的性質得到
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的取值范圍.
(1)根據(jù)正弦定理,可將

轉化為
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,又由余弦的二倍角公式轉化為
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2分
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4分
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,因為在銳角
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中,所以
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5分
(2)由(1)與正弦定理可得
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所以
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6分

8分
因為
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所以
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10分.
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