【答案】
分析:利用配方法求出方程x
2-2x-

=0的解,將求出的解代入x
2-(k+2)x+

=0中,得到關(guān)于k的方程,求出方程的解即可得到k的值.
解答:解:x
2-2x-

=0,
移項得:x
2-2x=

,
配方得:x
2-2x+1=

,即(x-1)
2=

,
開方得:x-1=±

,
解得:x
1=

,x
2=-

,
△=(k+2)
2-9≥0,即k≥1或k≤-5,
①根據(jù)題意把x=

代入x
2-(k+2)x+

=0得:(

)
2-

(k+2)+

=0,
解得:k=

;
②把x=-

代入x
2-(k+2)x+

=0得:(-

)
2+

(k+2)+

=0,
解得:k=-7,
綜上所述,k的值為-7或

.
點評:此題考查了一元二次方程的解法,以及一元二次方程的解,方程的解即為能使方程左右兩邊相等的未知數(shù)的值.