解:(1)原式=1+9-1
=9;
(2)(-x
2y
3)÷(2x
5y
6)•(-
xy
2)
=(-
x
-3 y
-3)•(-
xy
2)
=
x
-2 y
-1
=
;
(3)原式=[x
2+4xy+4y
2-(3x
2-xy+3xy-y
2)-5y
2]÷2x
=(-2x
2+2xy)÷2x
=-x+y,
當(dāng)x=-2,y=
時(shí),原式=2+
=
;
(4)如圖所示:△ABC即為所求.
分析:(1)此題涉及到乘方、負(fù)整數(shù)指數(shù)冪、零次冪,首先根據(jù)各知識(shí)點(diǎn)進(jìn)行計(jì)算,再計(jì)算有理數(shù)的加減法即可;
(2)首先計(jì)算單項(xiàng)式除法,再計(jì)算單項(xiàng)式乘法,最后把負(fù)指數(shù)變?yōu)檎笖?shù)即可;
(3)首先根據(jù)整式的運(yùn)算進(jìn)行化簡(jiǎn),再代入數(shù)進(jìn)行計(jì)算;
(4)首先利用作一個(gè)角等于已知角的方法作∠ABC=∠α,再利用圓規(guī)截取AB=a,BC=b,最后連接BC即可.
點(diǎn)評(píng):此題主要考查了乘方、負(fù)整數(shù)指數(shù)冪、零次冪、整式的混合運(yùn)算、作圖,關(guān)鍵是掌握課本基礎(chǔ)知識(shí),才能進(jìn)行正確的計(jì)算.