Question

（本小題滿分11分）
如圖，已知等邊三角形ABC中，點(diǎn)D，E，F(xiàn)分別為邊AB，AC，BC的中點(diǎn)，M為直線
BC上一動(dòng)點(diǎn)，△DMN為等邊三角形（點(diǎn)M的位置改變時(shí)，△DMN也隨之整體移動(dòng)）．
（1）如圖①，當(dāng)點(diǎn)M在點(diǎn)B左側(cè)時(shí)，請(qǐng)你判斷EN與MF有怎樣的數(shù)量關(guān)系？點(diǎn)F與直線EN有怎樣的位置關(guān)系？都請(qǐng)直接寫(xiě)出結(jié)論，不必證明或說(shuō)明理由；
（2）如圖②，當(dāng)點(diǎn)M在BC上時(shí)，其它條件不變，（1）的結(jié)論中EN與MF的數(shù)量關(guān)系是否仍然成立?若成立，請(qǐng)利用圖②證明；若不成立，請(qǐng)說(shuō)明理由；
（3）若點(diǎn)M在點(diǎn)C右側(cè)時(shí)，請(qǐng)你在圖③中畫(huà)出相應(yīng)的圖形，并判斷（1）的結(jié)論中EN與MF的數(shù)量關(guān)系及點(diǎn)F與直線EN的位置關(guān)系是否仍然成立?若成立?請(qǐng)直接寫(xiě)出結(jié)論，不必證明或說(shuō)明理由．

Answer 1

（1）判斷：EN與MF相等（或EN=MF），點(diǎn)F在直線NE上   ······ 3分
（說(shuō)明：答對(duì)一個(gè)給2分）
（2）成立．································ 4分
證明：
法一：連結(jié)DE，DF．   ··········································································· 5分
∵△ABC是等邊三角形，∴AB=AC=BC．
又∵D，E，F(xiàn)是三邊的中點(diǎn)，
∴DE，DF，EF為三角形的中位線．∴DE=DF=EF，∠FDE=60°．
又∠MDF+∠FDN=60°，∠NDE+∠FDN=60°，
∴∠MDF=∠NDE． ················································································ 7分
在△DMF和△DNE中，DF=DE，DM=DN，∠MDF=∠NDE，
∴△DMF≌△DNE． ··············································································· 8分
∴MF=NE．      　··············································································· 9分

法二：
延長(zhǎng)EN，則EN過(guò)點(diǎn)F．    ······································································ 5分
∵△ABC是等邊三角形，∴AB=AC=BC．又∵D，E，F(xiàn)是三邊的中點(diǎn)，∴EF=DF=BF．  
∵∠BDM+∠MDF=60°，∠FDN+∠MDF=60°，∴∠BDM=∠FDN．······················· 7分
又∵DM=DN，∠ABM=∠DFN=60°，∴△DBM≌△DFN．································· 8分
∴BM=FN．∵BF=EF， ∴MF=EN．···························································· 9分
法三：
連結(jié)DF，NF． ······················································································ 5分

∵△ABC是等邊三角形，∴AC=BC=AC．
又∵D，E，F(xiàn)是三邊的中點(diǎn)，∴DF為三角形的中位線，∴DF=AC=AB=DB．
又∠BDM+∠MDF=60°，∠NDF+∠MDF=60°，∴∠BDM=∠FDN． ………………7分
在△DBM和△DFN中，DF=DB，
DM=DN，∠BDM=∠NDF，∴△DBM≌△DFN．
∴∠B=∠DFN=60°．…………………………………………………………………8分
又∵△DEF是△ABC各邊中點(diǎn)所構(gòu)成的三角形，
∴∠DFE=60°．∴可得點(diǎn)N在EF上，∴MF=EN．………………………………9分
（3）畫(huà)出圖形（連出線段NE）， ······························································· 10分
MF與EN相等及點(diǎn)F在直線NE上的結(jié)論仍然成立（或MF=NE成立）． ················ 11分

解析