u-2v
u+2v
-
2
u2-4v2
分析:首先通分,將原式通分為
(u-2v)2
(u+2v)(u-2v)
-
2
(u+2v)(u-2v)
,然后利用同分母的分式相加減的運算法則求解即可求得答案.
解答:解:
u-2v
u+2v
-
2
u2-4v2
=
(u-2v)2
(u+2v)(u-2v)
-
2
(u+2v)(u-2v)
=
u2-4uv+v2-2 
(u+2v)(u-2v)
點評:此題考查了異分母分式的加減運算法則.注意先通分,再利用同分母的分式相加減的運算法則求解即可,注意運算結(jié)果需化為最簡.
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