A
分析:首先將(2+1)(22+1)(24+1)(28+1)(216+1)乘以(2-1),利用平方差公式求解,即可求得232-1+1,繼而求得答案.
解答:(2+1)(22+1)(24+1)(28+1)(216+1)+1
=(2-1)(2+1)(22+1)(24+1)(28+1)(216+1)+1
=(22-1)(22+1)(24+1)(28+1)(216+1)+1
=(24-1)(24+1)(28+1)(216+1)+1
=(28-1)(28+1)(216+1)+1
=(216-1)(216+1)+1
=232-1+1
=232.
故選A.
點評:此題考查了平方差公式的應(yīng)用.注意掌握平方差公式:(a+b)(a-b)=a2-b2.